有一对正常齿制的标准直齿圆柱齿轮机构,搬运时丢失了大齿轮,需要配制。现测得两轴间距离a=112.5mm,小齿轮齿数z1=38,顶圆直径d=100mm,求大齿轮的模数、齿数、分度圆直径、齿顶圆直径、齿根圆直径、基圆直径、分度圆齿距、齿厚、齿槽宽、标准顶隙

da1=m(z1+2ha*) m=da1/(z1+2ha*)=100/(38+2×1)=2.5mm a=m(z1+z2)/2 z2=2a/m-z1=2×100/2.5-38=52 d2=mz2=2.5×52mm=130mm da2=m(z2+2ha*)=2.5×(52+2×1)=135mm df2=d2-2hf=130-2×2.5×(1+0.25) =123.75mm db2=d2cosα=130cos20°=122.2mm p=πm=3.14×2.5=7.85mm s=p/2=3.925mm e= p/2=3.925mm c=c*m=0.25×2.5=0.625mm