参考代码：
h = 0
leap = 1
from math import sqrt
for m in range(1,201):
k = int(sqrt(m + 1))
for i in range(2, k + 1):
if m % i == 0:
leap = 0
break
if leap == 1:
print('%-4d' % m)
h += 1
if h % 10 == 0:
print("",end="")
leap = 1
print('The total is %d'%h)
答案是47。
问题 更新时间2023/6/29 14:37:00
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